??
log x = a + 1/2 log b - log c
log x = a + log √b - log c
log x = a + log (√b/c)
10^[a + log (√b/c)] = x
x = 10^[log 10ª + log (√b/c)]
x = 10^[log 10ª(√b/c)]
x = 10ª√b/c
Resposta:10ª√b/c
Espero que seja isso,
Lcs
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Verified answer
log x = a + 1/2 log b - log c
log x = a + log √b - log c
log x = a + log (√b/c)
10^[a + log (√b/c)] = x
x = 10^[log 10ª + log (√b/c)]
x = 10^[log 10ª(√b/c)]
x = 10ª√b/c
Resposta:10ª√b/c
Espero que seja isso,
Lcs