a)log de 6 na base 5 b)log de 2/3 na base 5, c)log de 1,5 na base 5, d)log de 2 na base 3, e)log de 3 na base 2, f)log de 8 na base 5, g) log de 24 na base 5, h) log de 9/8 na base 5, i)log de √3 na base 5, l)log de 4√3 índice 4, na base 5, k) log de 12 na base raiz de cinco
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a) log [5] 6 = log [5] 2 * 3 = log [5] 2 + log [5] = 0,43 + 0,68 = 1,11
b)log[5] 2/3 = log[5] 2 - log[5] 3 = 0,43 - 0,68 = -0,25
c) log[5] 1,5 = log[5] 15/10 = log[5] 3/2 = log[5] 3 - log[5] 2 = 0,25
d) log [3] 2 = log [5] 2/log[5] 3 = 0,43/0.68 = 0,63
e) log [2] 3= log[5] 3/log[5] 2 = 0,68/0,43 = 1,58
f) log [5] 8 = log[5] 2^3 = 3 * log[5] 2 = 3 * 0,43 = 1,29
g) log[5] 24 = log[5] 2^3 * 3 = log[5] 2^3 + log[5] 3 = 3 * log[5] + 2 log[5] 3 = 3 * 0,43 + 0,68 = 1,97
h) log[5] 9/8 = log[5] 9 - log[5] 8 = log[5] 3^2 - log[5] 2^3 = 2 * log[5] 3 - 3 * log[5] 2 = 2 * 0,43 - 3 *
0,68 = 0,86 - 2,04 = - 1,18
i) log [5] √3 = log[5] 3^1/2 =1/2 * log[5] 3 = 1/2 * 0,68 = 0,34
l) log [5] ∜3 = log [5] 3^1/4= 1/4 log[5] 3 = 1/4 * 0,68 = 0,17
k) log[√5] 12 = log [5^1/2] 2^2 * 3 = 2 * log[5] 2^2 + 2 * log 3 = 2 * 2 log[5] 2 + 2 log [5] 3 = 4 * 0,43 +
2 * 0,68 = 1,72 + 1,36 = 3,08
Ufa! Espero ter ajudado vc.