how do I put 3.3 k ohms, 1 k ohms, and 2.2 k ohms into a series parallel circuit with a total resistance of approximately 1.43 k ohms?
*also you have to use all 3 resistors *
(3300 + 1000) = 4300 ohms in a series connection.
Parallel that with 2200, = (4300 x 2200)/ (4300 + 2200), = 1.455k ohms.
That uses all 3.
I don't think you can. There are only a few possibilities.
3.3 and 2.2 in parallel with 1 in series. This is 2.32
1 and 2.2 in parallel with 3,3 in series. This will be over 3.3
1 and 3.3 in parallel with 2,2 in series. This will be over 2.2
3.3 in series with 1, in parallel with 2.2, for 4.3•2.2/6.5 = 1.46 (very close)
2.2 in series with 1, in parallel with 3.3 for 3.2•3.3/6.5 = 1.62
3.3 in series with 2.2, in parallel with 1, this will be <1
.
The closest you are going to get is to put the 3.3k in parallel with the 2.2K and get 1.3K.
No combination will get any closer.
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(3300 + 1000) = 4300 ohms in a series connection.
Parallel that with 2200, = (4300 x 2200)/ (4300 + 2200), = 1.455k ohms.
That uses all 3.
I don't think you can. There are only a few possibilities.
3.3 and 2.2 in parallel with 1 in series. This is 2.32
1 and 2.2 in parallel with 3,3 in series. This will be over 3.3
1 and 3.3 in parallel with 2,2 in series. This will be over 2.2
3.3 in series with 1, in parallel with 2.2, for 4.3•2.2/6.5 = 1.46 (very close)
2.2 in series with 1, in parallel with 3.3 for 3.2•3.3/6.5 = 1.62
3.3 in series with 2.2, in parallel with 1, this will be <1
.
The closest you are going to get is to put the 3.3k in parallel with the 2.2K and get 1.3K.
No combination will get any closer.