Triangles doubt.?

Triangle ABC is right-angled at B. D and N and points on AC and AB respectively such that DN is parallel to BC. Draw DM perpendicular to BC. Prove that:

DM² = (DN)*(MC)

DN² = (AN)*(DM)

Update:

Joining midpoints is not the only way to get parallel lines in a right triangle! Why do you keep misunderstanding? Or did you not read Additional Details?

D and N can be anywhere on AC and AB respectively. You can still get parallel lines DN and BC. And naturally, it follows that M is not the midpoint of BC.

You guys are dealing with a former Top Contributor in Mathematics here.

OR if you need the source of this:

This is from Exercise 6.6, question 2 of the NCERT maths textbook for Class X (NEW). You can see the Online textbook here:

http://www.ncert.nic.in/

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