what is the real value of x in the equation log2 24-log2 3=log5x?
if possible show me how u got ya answer and if u get the time can u work this other equation: The numbers are reciprocals if their product is equal to 1. if x and y are reciprocal and x>1, then y must be
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Verified answer
log2 24-log2 3= log2 (24/3) = log2 (8)=3.
So log5 x=3 thus x=5^3=125.
log2 24 - log2 3 = log5 x
Since 24 and 3 have the same log base of 2, we can combine them.
log2 (24/3) = log5 x
log2 8 = log5 x
We know that 8 is actually 2 to the power of 3, or rather 8 = 2^3.
Thus,
log2 2^3 = log5 x
3 = log5 x
x = 5^3
x = 125
NOTE: Remember that logx x is always 1. Thus 3log2 2 is 3(1).
log2 24-log2 3=log5x
log2 (24/3)=log5 x
log2 8=log5 x
we know from the definition of logs that
log2 8=3 so
log5 x =3 & from the definition of logs
x=5^3=125
y=1/125=.008