Verified answer

x = 0.

because -36/(0)^2 = -36/0 is undefined

is this log base 10 to the polynomial or log base 10 to ten then expanded with assistance from the polynomial. v=base ^=exponent if its the 1st manner then change the issue around: Logv10 of (x^2-12x+36)=2 2 will grow to be exponent of base and that equals the polynomial 10^2=(x^2-12x+36) in simple terms expression a hundred=(x^2-12x+36) minus a hundred from the two facets (x^2-12x-sixty 4)=0 ingredient out (x-sixteen)(x+4)=0 x=sixteen x=4 if that's the 2nd manner then logv10 of 10 is equivalent to at least one by using fact 10^a million=10 so (x^2-12x+36)=2 subtract 2 (x^2-12x+34)=0 quadratic formulation to sparkling up 6+ sq. root of 2 and six- sq. root of 2

As it's written x = 6 is the only place where the function doesn't exist

(x^2 - 36) / (x^2 - 12x + 36) =>

((x - 6) * (x + 6)) / ((x - 6) * (x - 6)) =>

(x + 6) / (x - 6)

That's its most simplified form