A raiz da equação 2(x+1)/3 - 3(x+2)/4 = x+1/6 pertence ao intervalo:?
a) [0,2]
b) [-3,-1]
c) [-2,0]
d) [-6,-3]
e) [2,6]
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a) [0,2]
b) [-3,-1]
c) [-2,0]
d) [-6,-3]
e) [2,6]
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Verified answer
2(x+1)/3 - 3(x+2)/4 = x+1/6 ... multiplicando por 12= mmc(3,4,6)
8x+8 -9x-18=12x+2
-x-10=12x+2
-12=13x
x= -12/13= -0,92
Resp
c) [-2,0]