Let F be a field and suppose that (x-a) divides f(x) in F[x]. Prove f(a)=0.
To say that (x - a) divides f(x) means that there exists q(x) in F[x] such that
f(x) = q(x)*(x - a).
So f(a) = q(a)*(x - a) = q(a)*0 = 0.
ouch! that is tough.
I would use the division by zero proof: if F[x] can be divided, it certainly cannot be divided by 0.
that's kind of weak. maybe rearrange the equation and use the product rule.
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To say that (x - a) divides f(x) means that there exists q(x) in F[x] such that
f(x) = q(x)*(x - a).
So f(a) = q(a)*(x - a) = q(a)*0 = 0.
ouch! that is tough.
I would use the division by zero proof: if F[x] can be divided, it certainly cannot be divided by 0.
that's kind of weak. maybe rearrange the equation and use the product rule.