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[1 + (2/x)] / (3/4) I hope this expression accurately describes what your problem is.

Take the reciprocal of 3/4, which is 4/3, and multiply it by (1 + (2/x))

[(4/3) + (4/3)(2/x) = [(4/3) + (8/3x)]. The common denominator is 3x so multiply by 3x and cancel where appropriate.

[3x(4/3) + 3x(8/3x)] =

4x + 8. Factor out 4. 4(x + 2). Answer.

Ye you are not sleepy. So alert to follow me. Ok.

your sum has to be this way. ie {1+ (2/x)} / (3/4)

When we divide by fraction we simply reciprocate the denominator and do the multiplication.

So {1+ (2/x)} * 4/3

Now in the first factor we take lcm x. So multiplying the first and second terms by x we get,

(x + 2) / x * 4/3 = 4(x+2) / 3x

This is 4 times x+2 over 3 times x.