Algebra 1!!!!!!!!!!!!?
1) Find the slope of the line at passes through (-4,-8) and (-4,2).
A. 0
B. 3/4
C. 5/4
D. undefined
2) Find the slope of the line at passes through (3,6) and (1,-4)
A. 5
B. -1
C. -2
D. undefined
3) Find the slope of the line at passes through (-4,2) and (2,2)
A. -2/5
B. 0
C. 1
D. undefined
4) Find the slope of the line at passes through (-4,4) and (4,-2)
A. -4/3
B. -3/4
C. 1/4
D. undefined
5) Write the point-slope form of the line that passes through (4,-1) with slope 2.
A. y+1 = 2(x-4)
B. y-1 = 2(x+4)
C. y-4 = 2(x+1)
D. y+4 = 2(x-1)
Update:If i knew how to do the formula i wouldn't be asking how to do it.
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Verified answer
1 m=(y2-y1)/(x2-x1)
=(-8-2)/(-4-(-4))=-10/0=undef
"D"
2 m=(y2-y1)/(x2-x1)
=(6-(-4))/(3-1)=10/2=5
"A"
3 m=(y2-y1)/(x2-x1)
=(2-2)/(-4-2)=0/-6=0
"B"
4 m=(y2-y1)/(x2-x1)
=(4-(-2))/(-4-4)=-6/8=-3/4
"C"
5 m=(y2-y1)/(x2-x1)
2=(y+1)/(x-4)
"A"
My friend, don't refer to it as slope. Refer to it as gradient. You might lose marks. (Unless you're American and you guys do it differently there, ask your teacher).
To work out the slope (gradient, whatchamacallit) you use the equation (Y2-Y1)/(X2-X1). This is known as The difference in Y over The difference in X, dy/dx. AKA Differentiation. You may already come across the term.
Example, question 4:
-2-4/4-(-4)
Equals= -6/8 = -3/4
Hope this helps.
The equation to find slope is: slope=y2-y1/x2-x1
To find the slope you use this formula y-mx+b.
Point slope form is: y-y1=m(x-x1)
You can figure it out from there.
for 1,2,3, and 4 simply do this y2-y1/x2-x1