Verified answer

The general point for the y intercept of a curve/line is (0,b)

We are told that we want b <=0

The maximum slope will occur when b = 0

So we need to find the slope of a line passing through the points (-3, -2) and (0,0)

The slope of the line can be given by the eqn

Slope = Rise/Run = (Y2 - Y1)/(X2 - X1)

Slope = (0 - - 2) / (0 - - 3)

Slope = 2/3

The maximum slope will be 2/3 if the slope is increased any further b will increase greater than zero and if it is decreased b will decrease to less than 0

The y-intercept is the point at which any line crosses the y-axis. This is the line that goes up and down.

Any point that is a y-intercept will have an x value of 0.

What you need here is the greatest non-positive number, 0.

We now have the coordinates. x of y-axis is 0. Greatest number that is not positive for y, 0.

(x,y) = (0,0)

m= (y1-y2)/(x1-x2)

,,,,,,,,,,,,(-2 - 0),,,,,,,,,,,,,,-2,,,,,,,,2

m,,,,=,,,,---------,,,,,,,=,,,,,-- ,,= ,,--

,,,,,,,,,,,,(-3 - 0),,,,,,,,,,,,,,-3,,,,,,,,3

you already know that the 1st place that b can start to be beneficial is nice above 0 on the y axis. so which you positioned your preliminary element to (-3,-4) and your very final element to (0,0) the slope m=(yf-yibffa6f5626cc136a96173d20b87557exf-xi) m= [(0) - (-4)] / [(0) - (-3)] = (0) - (-4)] / [(0) - (-3)

sorry to say,but i am not getting.