Algebra/Algorithm Help! (C Programming)?
Given:
Concentration = (ep-el)/(ep-em)*(em/el)^1/3*100
Where "ep" and "em" are constant. Write a "C" program to determine "el" for concentration 0 to 100 step 10.
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Given:
Concentration = (ep-el)/(ep-em)*(em/el)^1/3*100
Where "ep" and "em" are constant. Write a "C" program to determine "el" for concentration 0 to 100 step 10.
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Verified answer
It's a simple for loop, but the tricky part is the exponentiation. You can't do (em/el)^1/3*100 directly. Instead, you will have to use the fact that a^x = e^[ x log a ]. You have to include math.h to get the log( ) and the exp( ) functions. And when you compile it, you will need to use the -lm option (assuming you're in a command-line Unix/Linux environment).