X^2-2x+10=0
X=(7x-3)^1/2
Me equivoque en la segunda D: es
X=(7x-3)^1/2 -1
x^2 - 2x + 1 = 10 + 1
(x-1)^2 = 11
x-1 = ±√11
x = 1 ±√11
2:
x^2 = 7x - 3
x^2 - 7x + 3 = 0
[7 ± √(49 - 12)] / (2)
[7±√37] / 2
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Verified answer
x^2 - 2x + 1 = 10 + 1
(x-1)^2 = 11
x-1 = ±√11
x = 1 ±√11
2:
x^2 = 7x - 3
x^2 - 7x + 3 = 0
[7 ± √(49 - 12)] / (2)
[7±√37] / 2