Sabendo que:
log (a.b) = log a + log b e que
log(a/b) = log a - log b, temos:
.
log 15 = log (30/2) = log (3.10/2) = log 3 + log 10 - log 2
= 0,48 + 1 - 0,30 = 1,18
log5 = log(10/2) = log10 - log2 = 1 - 0,30 = 0,70
log15 = log(5.3) = log5 + log3 = 0,70 + 0,48 = 1,18
log 15 = log 3*5= log 3*10/2 = log 3 + log 10 - log 2
log 15 = 0,48 + 1 - 0,30 = 1,18
=======================
log(15) = log(30/2) = log(10) + log(3) - log(2) = 1 + 0,48 - 0,30 = 1,18
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Verified answer
Sabendo que:
log (a.b) = log a + log b e que
log(a/b) = log a - log b, temos:
.
log 15 = log (30/2) = log (3.10/2) = log 3 + log 10 - log 2
= 0,48 + 1 - 0,30 = 1,18
log5 = log(10/2) = log10 - log2 = 1 - 0,30 = 0,70
log15 = log(5.3) = log5 + log3 = 0,70 + 0,48 = 1,18
log 15 = log 3*5= log 3*10/2 = log 3 + log 10 - log 2
log 15 = 0,48 + 1 - 0,30 = 1,18
=======================
log(15) = log(30/2) = log(10) + log(3) - log(2) = 1 + 0,48 - 0,30 = 1,18
pronto