Calcule o volume da pirâmide quadrangular regular cujo apótema lateral mede 13cm e a aresta da base mede 10cm
h²=a² + b²
13²= 5² +b²
169= 25 +b²
169 - 25 = b²
144 = b²
b = raíz de 144
b = 12 (altura da piramide)
Vpiramide = Ab x H / 3
V = lado x lado x 12 / 3
V = 10x10x12 / 3
V = 1200 / 3
V = 400 cm³
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Verified answer
h²=a² + b²
13²= 5² +b²
169= 25 +b²
169 - 25 = b²
144 = b²
b = raíz de 144
b = 12 (altura da piramide)
Vpiramide = Ab x H / 3
V = lado x lado x 12 / 3
V = 10x10x12 / 3
V = 1200 / 3
V = 400 cm³
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