Let f(x,y) = 4(x^2)y + 8ln(xy)
Evaluate df/dx at (x, y) = (4, 1)
Evaluate df/dy at (x, y) = (4, 1)
δf/δx = 8xy + 8 / x ; δf/δy = 4 x² + 8 / y
To get df/dx you just take the derivative as if y was a constant (which if you are doing 3-d calc this should be simple at this point)
then just plug in x=4 and y=1 to get the answer.
Same with df/dy, you treat x as a constant (derivative of 4x^2y with respect to y is just 4x^2)
âf/âx = 8xy + 8/x = 8*4*1 + 8/4 = 34 at (4, 1)
âf/ây = 4x^2 + 8/y = 8*4^2 + 8/1 = 136 at (4, 1)
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δf/δx = 8xy + 8 / x ; δf/δy = 4 x² + 8 / y
To get df/dx you just take the derivative as if y was a constant (which if you are doing 3-d calc this should be simple at this point)
then just plug in x=4 and y=1 to get the answer.
Same with df/dy, you treat x as a constant (derivative of 4x^2y with respect to y is just 4x^2)
âf/âx = 8xy + 8/x = 8*4*1 + 8/4 = 34 at (4, 1)
âf/ây = 4x^2 + 8/y = 8*4^2 + 8/1 = 136 at (4, 1)