Calculate the acceleration of a 1500 kg car if it can stop from 30 km/h on a dime (1.7cm diameter)?
How many 's is this?
What is the force felt by the 70 kg occupant of the car?
30 km/h = 30 000m / 3600s = 8.33 m/s
Initial vel, u = 8.33m/s
d = 1.70^-2 m
v = 0
Using .. v² = u² + 2ad
a = - u² /2d
a = - (8.33)² / (2 x 1.70^-2) .. .. .. ..►a = - 2041.0 m/s²
In g's .. .. 2041m/s² / 9.80m/s² .. .. ►208.25 g
Av.force, F = m x a .. .. F = 70.0kg x -2041.0m/s² .. .. ►F = (-) 1.43^5 N
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Verified answer
30 km/h = 30 000m / 3600s = 8.33 m/s
Initial vel, u = 8.33m/s
d = 1.70^-2 m
v = 0
Using .. v² = u² + 2ad
a = - u² /2d
a = - (8.33)² / (2 x 1.70^-2) .. .. .. ..►a = - 2041.0 m/s²
In g's .. .. 2041m/s² / 9.80m/s² .. .. ►208.25 g
Av.force, F = m x a .. .. F = 70.0kg x -2041.0m/s² .. .. ►F = (-) 1.43^5 N