Contenporaty Abs Algebra?
having problem on the subject, getting ready for final, can someone explain me how to find the order of permutations on
(1 3 5) (2 4 6 7 8 9 10)
Update:how u got that answer. if I get the LCM, I get (3, 7) = 21, am I wrong?
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I'm assuming that you notation means that 1, 3 and 5 must be in the first three numbers and that the others must be the last 7 numbers. In that case there are 3! ways of positioning the first three numbers and 7! ways of positioning the last seven numbers for a total of:
3! * 7! = 30240