convert [sqrt(2) + j sqrt(2)] / (1 + j sqrt(3)) to polar form.
The answer is e^j(-pi/12) ... how?!
Update:Alright so the above is in cartesian form. They want me to convert this to polar form. Here is my attempt:
multiply by the complex conjugate and you are left with the following:
[sqrt(2) + j (sqrt(2)) - j (sqrt(6)) + sqrt(6)] / 4
I can't get past this part. Obviously I can get an approximation of the answer by knowing that:
r = sqrt(a^2 + b^2) where a is the real part and b is the complex part of the cartesian equation.
and theta = arctan (y/x) but this won't give me Euler's equation as the same answer as the back of the book states it.
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Verified answer
I'd convert the numerator and denominator first. Division is easier in polar than in Cartesian.
Each complex number has magnitude 2. (√2)² + (√2)² = 1² + (√3)² = 4 = 2².
The numerator is the first quadrant with
cos θ = √2 / 2
θ = π/4
...so the numerator is 2e^(i π/4)
The denominator is also in the first quadrant with
cos φ = 1/2
φ = π/3
... so the denominator is
Divide: 2e^(i π/4) / [2e^(i π/3)] = (2/2) e^[i π/4 - i π/3] = e^(-π/12)
what.
i-im sorry what?
are-are you..do you need somthing? orrrr...
...
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