A 0.50 mol sample of oxygen gas is confined at 0 degree celsius in a cylinder with a movable piston. The gas has an initial pressure of 1.0 atm. The piston then compresses the gas so that its final volume is half the initial volume. The final pressure of the gas is 2.2 atm. What is the final temperature of the gas in degrees celsius?
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Verified answer
PV = nRT
V = nRT / P = (0.50 mol) x (0.08205746 L atm /K mol) x (0 + 273K) / (1.0 atm) =
11.20 L initially
T = PV / nR = (2.2 atm) x (11.20 / 2) / ((0.50 mol) x (0.08205746 L atm /K mol)) =
300 K = 27°C