Write an equation of the line that is parallel to the given line and passes through the given point.
y = -2x - 1 (2,6)
The lines are parallel, so the "-2" bit remains the same.
The new equation will be y = -2x + b
(2, 6) is a solution, so we can plug those numbers in to find "b":
6 = -2(2) + b
6 = -4 + b
b = 10
SOLUTION: y = -2x + 10
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Since the other line is parallel, you know that the slope will be the same. So all you have to do is solve for the y-intercept (b).
y=-2x-b
6=-2(2)-b
6=-4-b
10=-b
b=-10
So your equation is:
y=-2x-10
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Verified answer
The lines are parallel, so the "-2" bit remains the same.
The new equation will be y = -2x + b
(2, 6) is a solution, so we can plug those numbers in to find "b":
6 = -2(2) + b
6 = -4 + b
b = 10
SOLUTION: y = -2x + 10
–––––––––––––––––––––––––
Since the other line is parallel, you know that the slope will be the same. So all you have to do is solve for the y-intercept (b).
y=-2x-b
6=-2(2)-b
6=-4-b
10=-b
b=-10
So your equation is:
y=-2x-10