log(base m)R^2 =x to an exponential equation?
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m^x = R^2
Hi
log(base m)R^2 =x
10^(log(base m)R^2= 10^x
m^(R^2) = 10^x
proof :
log(3) 2^2 = x
log(3) *4 = x
log(3) * 4 = x
0.477121254720* 4 = x
1.90848501888 = x
10^1.90848501888 = 81
or another way is :
3^4 = x
or
81 = x
Proof
10^(log(3) R^2= 10^x
10^(log(3) 2^2) = 10^ 1.90848501888 - Substutition o f x
10^log(3)* 4 =10^ 1.90848501888 - slove or taking the square
3^4 = 81 - taking the anti log of both sides of the equation
81 = 81 - sloving the power
it equals and check
Plugging this into the standard definition: Log(base a)x = y is the same as: a^y = x
this becomes: m^x = R^2
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Answers & Comments
Verified answer
m^x = R^2
Hi
log(base m)R^2 =x
10^(log(base m)R^2= 10^x
m^(R^2) = 10^x
proof :
log(3) 2^2 = x
log(3) *4 = x
log(3) * 4 = x
0.477121254720* 4 = x
1.90848501888 = x
10^1.90848501888 = 81
or another way is :
3^4 = x
or
81 = x
Proof
10^(log(3) R^2= 10^x
10^(log(3) 2^2) = 10^ 1.90848501888 - Substutition o f x
10^log(3)* 4 =10^ 1.90848501888 - slove or taking the square
3^4 = 81 - taking the anti log of both sides of the equation
81 = 81 - sloving the power
it equals and check
Plugging this into the standard definition: Log(base a)x = y is the same as: a^y = x
this becomes: m^x = R^2