Verified answer

the dinominator factors out to (x+3)*(x-4)

then do fraction decomposition

a(x-4) + b(x+3) = 5x+1

a+b=5

3b-4a = 1

-3a-3b=-15

7a=14

a=2

b=3

(5x+1)/(x^2-x-12) = 2/(x+3) + 3/(x-4)

(5x+1)(x-3)(x-4)=0

5x^3-34x^2+53x+12=0

This is actually undecomposable. But it is workable if the two equations were apart. Sorry dude, better luck next time.

x^2-x-12

(x+3)(x-4)=0

x+3=0 x-4=0

x=-3 x=4

5x+1

5x+1=0

5x=-1

x=-1/5