Verified answer

x^2-8x-8 doesn't factor in rational numbers. If you really need to, you can use the quadratic formula and the factor theorem to find:

(x - 4 + 2√6)(x - 4 - 2√6)

6x^2+7x-3 = (2x + 3)(3x - 1)

1. hey! okay so you put it into the X formula thingy. where you multiply the X squared with the -8 and the -8x is another number.

then you put -8 on the bottom of one of the X slots and -8 at the top since it is like the same answer.

then you try to find different numbers that can multiply to get -8 and if you add them together it also equals -8

so your answer should be not possible because no two numbers can multiply to be -8 and add to be -8.

2. okay so you use the X and multiply 6 times -3

then you plug it in so that you have -18 in the top slot and 7 in the bottom

then you try to find the two numbers

the numbers are 9 and -2

then you do (x+9) and (x-2)

x=9,-2

and if there is an equal sign

6x^2+7x-3=0

then it is x= -9,2 because you switch the negatives to positives and positives to negatives

but if there isnt an equal sign

6x^2+7x-3

then it is x= 9, -2

hope i helped!