Sometimes, I think I've got the gist of it, but then I end up getting some wrong. Can someone explain to me in a very simple way how to do this? I have quiz tomorrow.
What you do is you look for two numbers that multiply to give you (a x c) and which add together to give you "b" (So for instance, say the numbers are m and n)
And then: (ax + m)(ax - n) =0
And then simplify, so if it is (6x +3)(2x-1)=0
You can simplify the first bracket by making it (2x+1)
Hope that helps. If not google it. There's tonnes of stuff online.
Another great place to go is YouTube. You can learn way better there as your actually watching people do this kind of stuff.
Answers & Comments
Verified answer
A few rules you should remember:
(a+b)(a-b) = a^2 - b^2
(a+b)^2 = a^2 + 2ab + b^2
(a-b)^2 = a^2 - 2ab + b^2
General Form of Quad. Eqn: ax^2 + bx + c = 0
What you do is you look for two numbers that multiply to give you (a x c) and which add together to give you "b" (So for instance, say the numbers are m and n)
And then: (ax + m)(ax - n) =0
And then simplify, so if it is (6x +3)(2x-1)=0
You can simplify the first bracket by making it (2x+1)
Hope that helps. If not google it. There's tonnes of stuff online.
Another great place to go is YouTube. You can learn way better there as your actually watching people do this kind of stuff.
Good luck!
factorise it then expand it and see if it matches the questions, that's how you double check