1. The binomial can be factored using the difference of squares formula, because both terms are perfect squares.
(x^(2)+9)(x^(2)-9)
2. The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
answer: (x^(2)+9)(x-3)(x+3)
just go to www.mathway.com
I always go there....it helps alot:).....u can even graph
The binomial can be factored using the difference of squares formula, because both terms are perfect squares.
(x^(2)+9)(x^(2)-9)
The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
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Verified answer
1. The binomial can be factored using the difference of squares formula, because both terms are perfect squares.
(x^(2)+9)(x^(2)-9)
2. The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
answer: (x^(2)+9)(x-3)(x+3)
just go to www.mathway.com
I always go there....it helps alot:).....u can even graph
x^(4)-81
The binomial can be factored using the difference of squares formula, because both terms are perfect squares.
(x^(2)+9)(x^(2)-9)
The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
(x^2+9)(x-3)(x+3)
difference of two squares
(x^2+9)(x^2-9)
another difference of two squares
(x^2+9)(x+3)(x-3)
(x^2+9)(x^2-9)
i don't think you need to use the square root for this.
(x^2+9)(x-3)(x+3)
X times x times x times x - 81
(X^2 -9)(X^2+9) -> (X^2+9)(X-3)(X+3)
Final answer: (X-3)(X+3) (X^2+9)
You cant factor X squared plus nine, so you just factor X squared minus nine. your welcome!