Verified answer

its 24 different ways (1,2,3,4) ( 4!=4factorial)

1,2,3,4

1,2,4,3

1,3,2,4

1,3,4,2

1,4,2,3

1,4,3,2

2,3,4,1

2,3,1,4

2,4,1,3

2,4,3,1

2,1,3,4

2,1,4,3

3,4,2,1

3,4,1,2

3,2,1,4

3,2,4,1

3,1,4,2

3,1,2,4

4,3,2,1

4,3,1,2

4,2,3,1

4,2,1,3

4,1,2,3

4,1,3,2

Ok

Child 1 is A

Child 2 is B

Child 3 is C

Child 4 is D

So your question is how many combinations of A,B,C,D are possible?

The answer is 4 factorial or 4x3x2x1 = 24.

It is written 4! =24.

Hope this helps.

4 children can be arranged in a row in P(4) different ways

so the desired answer=P(4)=4!=24 ANS.