Maths problem. Average value. Calculus 2?
Let f(x) = tan(x). Show a geometric argument to explain why the average value of f(x) over the interval [-1, 1] is equal to 0, and find x such that f(x) is equal to this average value.
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tan(x) is an odd function ---> average value over [-1,1] is 0
To get the huge-unfold fee, in easy terms combine f(x) over the section and then divide that by utilising the considered necessary of a million over the section. (in distinctive words, for this concern in easy terms hit upon the considered necessary of f(x) over the section and divide it by utilising 20pi/6)