Verified answer

a)

sen30°=x/12

1/2=x/12

x=12*1/2

x=6

b)

tg30°=x/30

√3/3=x/30

x=30*√3/3

x=10√3

x=17

a) sen 30º = x/12

1/2 = x/12 >>>>>> meios pelos extremos...

2x = 12

x = 12/2

x = 6

b) tan 30º = x/30

raiz(3)/3 = x/30 >>>>>> meios pelos extremos

3x = raiz(3).30

x = 10raiz(3)

Abs