Verified answer

Ln e^e^10 easy, u the LNe^ cancel each other out living u with just e^10

The sum of logs is the product of a single log; difference is quotient; a coefficient becomes an exponent, so rewrite as singlr ln's: ln((x)(4^2) = ln (7/x) ln(16x) = ln (7/x) so 16x must = 7/x; 16x^2 = 7; x^2 = 7/16; x = +- sqrt7 / 4 Can't take the log of a negative number, so just sqrt7 / 4 is the answer