a) 1
b) -i
c) 2i
d) -i/2
e) i/2
i²=(√-1)²=-1
(1 - i)^-2 =1/(1 - i)²
1/(1-2i+i²) =1/(1-2i-1)
=1/(-2i)=-1/2i=-1*(2i)/(2i)*(2i)
=-2i/(-4)=i/2
Letra E
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Verified answer
i²=(√-1)²=-1
(1 - i)^-2 =1/(1 - i)²
1/(1-2i+i²) =1/(1-2i-1)
=1/(-2i)=-1/2i=-1*(2i)/(2i)*(2i)
=-2i/(-4)=i/2
Letra E