Para que o valor de k o ponto p(k,5) dista 4 do ponto q(3,1) ?
d²=(x-xo)²+(y-yo)²
4²=(3-k)²+(1-5)²
16=k²-6k+9+16
k²-6k+9=0
Delta=b²-4ac
Delta=(-6)²-4.1.9
Delta=36-36
Delta=0
k=6+0/2=3
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d²=(x-xo)²+(y-yo)²
4²=(3-k)²+(1-5)²
16=k²-6k+9+16
k²-6k+9=0
Delta=b²-4ac
Delta=(-6)²-4.1.9
Delta=36-36
Delta=0
k=6+0/2=3