Two hockey players are traveling at velocities of v1 = 11 m/s and v2 = -16 m/s when they undergo a head-on collision. After the collision, they grab each other and slide away together with a velocity of (-3.5) m/s. Hockey player 1 has a mass of 124 kg. What is the mass of the other player?
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Verified answer
you have to work out their momentum, and use momentum before = momentum after
(11 * 124) + (-16 * x) = -3.5 * (124 + x)
1364 + -16x = -434 + -3.5 x
1364 = -434 - 3.5x + 16x
1364 + 434 = -3.5x + 16x
1798 = 12.5x
143.84 = x
so the answer is 143.84 kg