PHYSICS PROBLEM!! Help!! PLease?
A juggler throws a ball from height of 0.950 m with a vertical velocity of +3.75 m/s and misses it on the way down. What is its velocity when it hits the ground?
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A juggler throws a ball from height of 0.950 m with a vertical velocity of +3.75 m/s and misses it on the way down. What is its velocity when it hits the ground?
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Verified answer
height reached above the release point is
h = v²/2g = (3.75)²/2•9.8 = 0.717 m
add to that the release height to get 1.667 total height reached.
Now how fast will the ball be moving when it hits the ground
h = v²/2g or
v = √(2gh) = √(2•9.8•1.667) = 5.72 m/s