Wind blows between two buildings at 45.0 m/s. If the door is 6'8 x 30'', how much net force is applied to the door pushing it out?
I really need help understanding the reasoning behing the calculations. All help appreciated.
Copyright © 2024 QUIZLS.COM - All rights reserved.
Answers & Comments
Verified answer
I think the formula is
F = ½ρAv²C
where ρ = density of fluid. air at about 0.075 lbm/ft³
and A = cross-sectional area = 6.67ft * 2.5ft ≈ 16.7 ft²
and v = velocity = 45 m/s = 148 ft/s
and C = drag coefficient = somewhere between 1 and 2 for a flat plate -- I'll take 2.
At least the units for this formula work out to be Newton's (and ρv² does not).
Then F = ½ * 0.075lbm/ft³ * 16.7ft² * (148ft/s)² * 2 = 27400 lbm·ft/s²
Divide by 32.2 to get to pounds force:
F ≈ 850 lbs
F=p.v2
where p = density of air
using impulse momentum equation, force is independent of area