If (r^2 / 4) ( 3x)^r (2 / 9x^2)^ 6-r can be simplified to k / x^3
Find the value of the constants k and r.
Thanks in advance
r^2/4 3^r x^r 2^(6-r) 9^(r-6) x^(2r - 12)
then
x^r x^(2r - 12) = x^-3
3r - 12 = -3
3r = 9
r = 3
k = 9/4 * 27 * 8 * 9^-3
= 2/3
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r^2/4 3^r x^r 2^(6-r) 9^(r-6) x^(2r - 12)
then
x^r x^(2r - 12) = x^-3
3r - 12 = -3
3r = 9
r = 3
k = 9/4 * 27 * 8 * 9^-3
= 2/3