.
a1.q^(n-1) = an........=> q=3/3√2 =1/√2
q^(n-1) = an / a1
(1/√2)^(n-1) = 3√2/16 / 3√2
(1/√2)^(n-1) = 3√2/16 . 1/3√2
(1/2¹/²)^(n-1) = 1/16
1/2^ (n/2 -1/2) = 1/2^ (4)
n/2 -1/2 = 4
n/2 = 4 +1/2
n/2 = 8/2 +1/2
n/2 = 9/2
n = 9 termos #
Copyright © 2024 QUIZLS.COM - All rights reserved.
Answers & Comments
.
a1.q^(n-1) = an........=> q=3/3√2 =1/√2
q^(n-1) = an / a1
(1/√2)^(n-1) = 3√2/16 / 3√2
(1/√2)^(n-1) = 3√2/16 . 1/3√2
(1/2¹/²)^(n-1) = 1/16
1/2^ (n/2 -1/2) = 1/2^ (4)
n/2 -1/2 = 4
n/2 = 4 +1/2
n/2 = 8/2 +1/2
n/2 = 9/2
n = 9 termos #