05.Resolva os sistemas abaixo, por escalonamento:
a) 2a-b+c-2=03a+2c=05b-2d+5=0b-c+d+4=0
b) 3x+y+2z=-4x-2y+z=02x+y-4z=-1
a)
2a-b + c +0= 2
0 +5b+ 0-2d=5
0 + b - c + d =4
3a+0 +2c+ 0=0 ==> 3L1 - L4
0 + b - c + d =4 ==> L2 - 5L3
0 - 3 +c+ 0=0 ===> 3L2+5L4
0 + 0 - 5c - 7d =-15
0 + 0 +5c - 6d = 12==> L3+L4
0 + 0 - 5c - 7d =15
0 + 0 + 0 - 13d = -3 ====> d=3/13
terminha o resto
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a)
2a-b + c +0= 2
0 +5b+ 0-2d=5
0 + b - c + d =4
3a+0 +2c+ 0=0 ==> 3L1 - L4
2a-b + c +0= 2
0 +5b+ 0-2d=5
0 + b - c + d =4 ==> L2 - 5L3
0 - 3 +c+ 0=0 ===> 3L2+5L4
2a-b + c +0= 2
0 +5b+ 0-2d=5
0 + 0 - 5c - 7d =-15
0 + 0 +5c - 6d = 12==> L3+L4
2a-b + c +0= 2
0 +5b+ 0-2d=5
0 + 0 - 5c - 7d =15
0 + 0 + 0 - 13d = -3 ====> d=3/13
terminha o resto