remember when there is a negative in front of a variable (-y,-x,-z) there is an imaginary 1 that exists. You must divide by that -1 on both sides of the equation.
-1x\-1 = 35/-1(cancels out and leaves you with just "x"
remember unlike signs = negative, like signs = positive. so since you're dividing 35 by -1, you will get x=-35
ok. properly in accordance to the orders of operation- you may do exponents first. So 3 to the 2nd potential is 9 and 3 to the third potential is 27. you have now 9+2 x 27. next, you may do multiplication. So 2 x 27 is fifty 4. you at the instant are left with 9+fifty 4 that's sixty 3!
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-x=35.
remember when there is a negative in front of a variable (-y,-x,-z) there is an imaginary 1 that exists. You must divide by that -1 on both sides of the equation.
-1x\-1 = 35/-1(cancels out and leaves you with just "x"
remember unlike signs = negative, like signs = positive. so since you're dividing 35 by -1, you will get x=-35
Whenever you see a negative number that looks like this: -x
It is actually like this -1(x). x is being multiplied by -1. To find positive x we divide negative one from the side it is on to the opposite side.
So 35 divided by -1 is -35.
divide 35 by -1 so x = -35
x= -35
Your "x" must always be a positive x.
So, when your x turns out to be a -x, here is the trick. MULTIPLY BOTH LEFT AND RIGH SIDES OF THE EQUATION BY -1
-x multiplied by -1 = +x and 35 x -1 = -35
So:
x = -35
x is -35 because divide negative one on both sides im in algebra 1 and in nth grade trust me because the variable can not be geative but 35 can
sorry but that's a little bit obvious:
-x=35
*switch sides:
x=-35
ok. properly in accordance to the orders of operation- you may do exponents first. So 3 to the 2nd potential is 9 and 3 to the third potential is 27. you have now 9+2 x 27. next, you may do multiplication. So 2 x 27 is fifty 4. you at the instant are left with 9+fifty 4 that's sixty 3!