(x-4)(x-5)=2
i have no idea how to get the solutions for this problem any help would be appreciated thanks and please show in detail.
x^2 - 5x - 4x + 20 - 2 = 0
x^2 - 9x + 18 = 0
x^2 - 3x - 6x + 18 = 0
x(x - 3) - 6(x - 3) = 0
(x - 6)(x - 3) = 0
x - 6 = 0 or x - 3 = 0
x = 6 or x = 3
First, distribute (multiply out the left hand side
(x - 4) (x - 5)
= x^2 -9x + 20
so
x^2 - 9x + 20 = 2
Now bring everything to one side (add -2 to both sides)
Factor
(x - 3)(x - 6) = 0
so either x = 3 or x = 6
x^2 - 9x +18 = 0
x = 6 or 3
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Verified answer
x^2 - 5x - 4x + 20 - 2 = 0
x^2 - 9x + 18 = 0
x^2 - 3x - 6x + 18 = 0
x(x - 3) - 6(x - 3) = 0
(x - 6)(x - 3) = 0
x - 6 = 0 or x - 3 = 0
x = 6 or x = 3
First, distribute (multiply out the left hand side
(x - 4) (x - 5)
= x^2 -9x + 20
so
x^2 - 9x + 20 = 2
Now bring everything to one side (add -2 to both sides)
x^2 - 9x + 18 = 0
Factor
(x - 3)(x - 6) = 0
so either x = 3 or x = 6
x^2 - 9x + 20 = 2
x^2 - 9x + 18 = 0
(x - 6)(x - 3) = 0
x = 6 or x = 3
x^2 - 9x + 20 = 2
x^2 - 9x +18 = 0
(x - 6)(x - 3) = 0
x = 6 or 3