Given a graph of positive slope that passes through point (-3,-4), what is its maximum possible slope before b, the y intercept, becomes a positive number?
I don't get this question& i don't know how to solve it, can you help?
explain step by step pleasee(:
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Line passes through (-3,-4), so y = m x + b becomes
-4 = m (-3) + b
When the y-intercept (b) first becomes positive, b < 0 crosses through b=0 to become b > 0.
So set b=0 and solve for m.
you know that the first place that b can begin to be positive is right above zero on the y axis.
so you set your initial point to (-3,-4) and your final point to (0,0)
the slope m=(yf-yi) / (xf-xi)
m= [(0) - (-4)] / [(0) - (-3)] = 4 / 3
The y-intercept is the factor at which any line crosses the y-axis. it is the line that is going up and down. Any factor it particularly is a y-intercept would have an x value of 0. What you like right here is the main suitable non-effective extensive style, 0. we've the coordinates. x of y-axis is 0. your best option extensive style that's no longer effective for y, 0. (x,y) = (0,0) m= (y1-y2)/(x1-x2) ,,,,,,,,,,,,(-2 - 0),,,,,,,,,,,,,,-2,,,,,,,,2 m,,,,=,,,,---------,,,,,,,=,,,,,-- ,,= ,,-- ,,,,,,,,,,,,(-3 - 0),,,,,,,,,,,,,,-3,,,,,,,,3
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