Before I ask this question, please get that I haven't learnt this and need help. No snarky comments, please and thank you.
A basketball is passed through the air. The height "h" of the ball in feet after the distance "d" in feet the ball travels horizontally is given by h=-d^2+10d+5. How far horizontally from the player passing the ball will the ball land on the ground?
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Verified answer
so
0 = -d^2 + 10d + 5
for domain d > 0
it doesn't factor,
but you can use quadratic formula or "complete the square" to solve.
for quad formula:
d = (-b ± √(b² - 4ac)) / (2a)
• a = -1
• b = 10
• c = 5
so
d = (-10 - sqrt((-10)^2 - 4(-1)(5))) / (2(-1)) ← ok to ignore other root (out of domain)
d = (10 + sqrt(100 + 20)) / 2
d ≈ 10.48 ft
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