i cant figure this out lol...need some help please...
3ax - 3bx - ay + by
thanks.
3ax - 3bx - ay + by =
(3ax - 3bx) - (ay - by) =
3x(a - b) - y(a - b) =
(3x - y)(a - b).
since your grouping its:
x=3 then y=4
and a is 6 bc y=4 z=5 then a=6 and b=7
so its like the question is:
6+7+3+4=20 which is the answer
= (3ax-ay) -(3bx - by)
= a(3x-y) - b(3x-y)
= (a-b)(3x-y)
= (3ax - ay) - (3bx - by)
= a(3x - y) - b(3x - y)
(3ax - ay) + (bx - 3by)
a(3x - y) - b(3y - x)
=
3x(a-b)-y(a-b)
(3x-y) * (a-b)
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Verified answer
3ax - 3bx - ay + by =
(3ax - 3bx) - (ay - by) =
3x(a - b) - y(a - b) =
(3x - y)(a - b).
since your grouping its:
x=3 then y=4
and a is 6 bc y=4 z=5 then a=6 and b=7
so its like the question is:
6+7+3+4=20 which is the answer
3ax - 3bx - ay + by
= (3ax-ay) -(3bx - by)
= a(3x-y) - b(3x-y)
= (a-b)(3x-y)
= (3ax - ay) - (3bx - by)
= a(3x - y) - b(3x - y)
= (a-b)(3x-y)
(3ax - ay) + (bx - 3by)
a(3x - y) - b(3y - x)
=
3x(a-b)-y(a-b)
=
(3x-y) * (a-b)