Verified answer

If the first compound is ethanoic acid its formula could be written C2H4O2 or CH3CO2H or most often CH3COOH showing the -COOH acid groop and the releasable H at the end.

The reaction is an acid base reaction and can be considered to take place in two ways depending on how much acid is available.

CH3COOH(aq) + Na2CO3(aq) --------> CH3COONa(aq) + NaHCO3(aq)

or

2CH3COOH(aq) + Na2CO3(aq) --------> 2CH3COONa(aq) + CO2(g) + H2O(l)