the difference of two numbers is 22. Twice the smaller exceeds the larger by 17.
find the numbers.
thank you very much!
ps show ur work so i can understand
The English always translates directly into algebra.
"the difference of two numbers is 22"
m - n = 22
"Twice the smaller exceeds the larger by 17"
2n - m = 17
Solve: add the two equations to eliminate m
2n - n = 17 + 22
n = 39
so from the first equation, m = 22 + n = 22 + 39 = 61
To check, twice the smaller is 78, which is 17 more than 61, OK
given this:
x-y=22
2y=x+17
you can solve for y:
x=2y-17
2y-17-y=22
2y-y=39
y=39
then plug in for y:
x-39=22
solve for x:
x=61
Check:
39(2)=78
78-61=17
(twice the smaller is 17 larger)
so ur answers are
61 and 39
your welcome :P
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Verified answer
The English always translates directly into algebra.
"the difference of two numbers is 22"
m - n = 22
"Twice the smaller exceeds the larger by 17"
2n - m = 17
Solve: add the two equations to eliminate m
2n - n = 17 + 22
n = 39
so from the first equation, m = 22 + n = 22 + 39 = 61
To check, twice the smaller is 78, which is 17 more than 61, OK
given this:
x-y=22
2y=x+17
you can solve for y:
x=2y-17
2y-17-y=22
2y-y=39
y=39
then plug in for y:
x-39=22
solve for x:
x=61
Check:
39(2)=78
78-61=17
(twice the smaller is 17 larger)
so ur answers are
61 and 39
your welcome :P