PLease help w/ physics problem?
An organ pipe is effectively open at one end, closed at the other, an has a fundamental frequency of 165Hz.
A) how long is the pipe?
B) what should be the fourth resonance frequency for this pipe?
More Questions From This User See All
Answers & Comments
Verified answer
(a).
¼ λ = L
¼ (v/f) = L
¼ (330/165) = L
L = 0.5 meter
(b).
¼ (v/f) (2n - 1) = L
¼ (330/f) (2 * 4 - 1) = 0.5
f = 1155 Hz