No, it is not 100% true.

To put it correctly, as x approaches infinity in your equation, the limit = 0, but the value is not ever equal to zero.

So, you could say this:

"as x approaches positive infinity, the limit of 1/e^x = 0"

As x approaches positive infinity, 1/e^x approaches 0 (not equal to 0).

Or, you may say:

lim x-->infinity 1/e^x = 0

Yes it is 100% true:

Think about it for a second... all e^1 really is is a number specifically (2.718) so if you square it now you have (7.39) if you ^3 or ^4 or all the way to infinity you are only getting a bigger number each time.

If you divide 1/ infinity you are approaching 0

I hope that helps

True. Or at least, x approaches 0.

True indeed !