The rectangular form of (-1, 5∏/6) is (-√3/2, 1/2).
NB : it's a +1 and not - 1
well, "rectangular form" ... i have never heard this before...
...G says it may be cartesian (from René Descartes) coordinates...
so the point M of polar coordinates is the radius r > 0 and the argument theta :
so (r , theta) = ( +1 , 5pi/6)
is positioned so that :
vector(OM) = r cos(theta) i + r sin(theta) j ( i and j unit vectors of x and y-axis)
= 1 cos5pi/6 . i + 1 sin5pi/6 . j
= -√3/2 i + (1/2) j
therefore the cartesian coordinates of M are : M ( -√3/2 ; 1/2)
et voilà !!
hope it' ll help !!
false. it should be (â3/2, -1/2)
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NB : it's a +1 and not - 1
well, "rectangular form" ... i have never heard this before...
...G says it may be cartesian (from René Descartes) coordinates...
so the point M of polar coordinates is the radius r > 0 and the argument theta :
so (r , theta) = ( +1 , 5pi/6)
is positioned so that :
vector(OM) = r cos(theta) i + r sin(theta) j ( i and j unit vectors of x and y-axis)
= 1 cos5pi/6 . i + 1 sin5pi/6 . j
= -√3/2 i + (1/2) j
therefore the cartesian coordinates of M are : M ( -√3/2 ; 1/2)
et voilà !!
hope it' ll help !!
false. it should be (â3/2, -1/2)