A diferença entre o numero de arranjos de 7 objetos tomados 3 a 3 e o numero de combinações de 7 objetos tomados 3 a 3 é:
A resposta é 175
oi, vamos lá:
A7,3-C7,3= 7!(7-3)!-7!/3!(7-3)!=
7!/4!-7!/3!4!=
7.6.5.4!/4!-7.6.5.4!/3!4!=
210-210/6=
210-25=175
saludos
7/4-7/3,4
7*6*5-7*6*5/3*2
210-35=175
A 7,3 – C 7,3 = [ 7! / (7 – 3)!] – [7! / 3! . (7 – 3 )! ] = [7 . 6 . 5 . 4! / 4!] – [ 7. 6 . 5 . 4! / 3! . 4! ] = 210 – 35 = 175
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oi, vamos lá:
A7,3-C7,3= 7!(7-3)!-7!/3!(7-3)!=
7!/4!-7!/3!4!=
7.6.5.4!/4!-7.6.5.4!/3!4!=
210-210/6=
210-25=175
saludos
7/4-7/3,4
7*6*5-7*6*5/3*2
210-35=175
A 7,3 – C 7,3 = [ 7! / (7 – 3)!] – [7! / 3! . (7 – 3 )! ] = [7 . 6 . 5 . 4! / 4!] – [ 7. 6 . 5 . 4! / 3! . 4! ] = 210 – 35 = 175