Please simplify this and show the work to this problem. Easy points if you know what your doing!
1/y^2/5
or in other words 1 over y to the root of 2/5 (2 over 5)
1/ (y^(2/5))
That's the same as y^(-2/5)
That's the same as the fifth root of y^(-2)
That's the same as 1 / the fifth root of y^(2)
I assume the last one is the one you're looking for.
Y^(-2/5)
Not sure how you expect to simplify this anymore...
1/ [ y^(2/5) ] = y^(-2/5)
You must not explain layout in words----USE BRACKETS.
This is already simple
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Verified answer
1/ (y^(2/5))
That's the same as y^(-2/5)
That's the same as the fifth root of y^(-2)
That's the same as 1 / the fifth root of y^(2)
I assume the last one is the one you're looking for.
Y^(-2/5)
Not sure how you expect to simplify this anymore...
1/ [ y^(2/5) ] = y^(-2/5)
You must not explain layout in words----USE BRACKETS.
This is already simple